If tana = 12/13 find value of 2sinacosa/cosa
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Step-by-step explanation:
Given tanθ=
13
12
cos
2
θ−sin
2
θ
2sinθcosθ
=
cos2θ
sin2θ
=tan2θ=
1−tan
2
θ
2tanθ
=
1−
169
144
2×
13
12
=
169
25
13
24
=
25
24×13
=
25
312
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