If tanA = 12/5 than find the value of 1+sinA/1-sinA
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1
Answer:
25
Step-by-step explanation:
tabA=12/5=p/b
so, by Pythagoras theorem:-h2=p2+b2
h2=12^2+5^2
h2=144+25
h=√169
h=13
a. t. q 1+sinA/1-sinA
(1+p/h)/(1-p/h)
(1+12/13)/(1-12/13)
(13+12/13)/(13-12/13)
(25/13)/(1/13)
25/13×13/1
25
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