Math, asked by kujurarpitaalka, 5 months ago

If tanA=15/8 and tanB=7/24, then what is cos(A+B)?​

Answers

Answered by techvoi007
0

Answer:

See, cos(A + B) is basically cosAcosB - sinAsinB

So, if tan(A) = 15/8, then clearly sin(A) = 15/17, cos(A) = 8/17

Also, tan(B) = 7/24, so clearly sin(B) = 7/25 and cos(B) = 24/25

These are from simple trigonometric identities.

Then, cos(A+B) = (192 - 105)/425

Which makes it 87 / 425.

Answered by mionean042
1

Answer:

tanA=15/8

p/b=15/8

so,h=\sqrt{p^{2} +b^{2}

=\sqrt{225+64

=\sqrt{289

=17

here,sinA=p/h=15/17

cosA=b/h=8/17

tanB=7/24

p/b=7/24

so,h=\sqrt{p^{2} +b^{2}

=\sqrt{49+576

=\sqrt{625

=25

here,sinB=p/h=7/25

cosB=b/h=24/25

Now,cos(A+B)=cosAcosB-sinAsinB

                      =8/17+24/25-(15/17+7/25)

                      =114/425

Step-by-step explanation:

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