If tanA=15/8,find the value of sin A
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Answered by
3
by taking tanA=15/8 draw a right angled triangle.
the sides making right angled triangle are 15 and 8
According to Pythagoras theorem,
15^2+8^2= diagonal^2
225+64=289
hence diagonal is √289
that is 17
sin A = opposite side / hypotenuse
Therefore ,
* sin A = 15 / 17 *
Hope it will help you.☺
the sides making right angled triangle are 15 and 8
According to Pythagoras theorem,
15^2+8^2= diagonal^2
225+64=289
hence diagonal is √289
that is 17
sin A = opposite side / hypotenuse
Therefore ,
* sin A = 15 / 17 *
Hope it will help you.☺
Answered by
0
Answer:
sinA=15/17
Step-by-step explanation:
tanA= opp/adj=15/8
BC=15& AB=8
therefore,using pythogoras rule AC²=AB²+BC²
=8²+15²
= 64+125
AC²=189
AC=17
THEREFORE,
SINA=opp/hypo=BC/AC
sinA=15/17
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