Question

if tanA=17/18 ,tanB=1/35 then cos(A+B)=​

Answer 1

Answer:

1/√2 . shingles duidgifiwjcucjwehcyycye7v

Answer 2

Answer:

Step-by-step explanation:

• Given: tan A=17/18, tan B= 1/35
• To find: cos(A+B)
• tan (A+B)= tan A+ tan B/ 1+ tan A/tan B
• $\frac{\frac{17}{18}+ \frac{1}{35} }{1-\frac{17}{18}\times\frac{1}{35} }$
• = 613/613
• =1
• tan(A+B)=1
• sec square (A+B)=1+1
• =2
• cos square (A+B)=1/2
• cos (A+B)=1/ root 2
• $\frac{1}{\sqrt{2} }$
• Hence, cos (A+B)= $\frac{1}{\sqrt{2} }$