Question

if tanA/2=0.6 find tanA​

Answer 1

For all values of the angle A we know that, tan A = 2 tan A/2/1 - tan^2 A/2

⇒ 2 tan A/2 = tan A ∙ tan^2 A/2

⇒ tan A ∙ tan^2 A/2 + 2 tan A/2 - tan A = 0

⇒ tan θ/2 = -2 ± √(4 + 4 tan^2 A)/2 tan A

⇒ tan θ/2 = -1 ± √1 + tan^2A/tan A

Answer 2

Step-by-step explanation:

Given: $\frac{TanA}{2} = 0.6$

To find: $TanA$

For calculation of TanA:

We know that for all values of ∠A, $Tan A= \frac{2TanA}{2} - Tan^{2}\frac{A}{2}$

⇒ $\frac{2TanA}{2}= TanA$ · $\frac{Tan^{2}A}{2}$

⇒ $Tan A$ · $\frac{Tan^{2}A}{2} + \frac{2TanA}{A} - Tan A=0$

⇒ $Tan\frac{0}{2} = -2$ ± $\sqrt{}(\frac{4+4Tan^{2}A)}{2TanA}$

⇒ $Tan\frac{0}{2} = -1$ ± $\sqrt{1}+\frac{Tan^{2}2A}{TanA}$

It is not possible to find the exact quadrant in which $\frac{A}{2}$ because the value of $TanA$ can have an infinite number of values.