Math, asked by harshj116, 1 year ago


If tanA =
√2 - 1, where A is an acute angle then the value of sinA.cosA will be​

Answers

Answered by amitnrw
0

sinA.cosA = √2/4   if  tanA = √2 - 1  & A is acute angle

Step-by-step explanation:

sinA.cosA

= CosATanACosA

= Cos²A. TanA

= TanA/Sec²A

= TanA / (1 + Tan²A)

=  (√2 - 1 ) / ( 1   + (√2 - 1)²)

= (√2 - 1 ) / ( 1   + 2 + 1 - 2√2)

= (√2 - 1 ) / ( 4 - 2√2)

= (√2 - 1 ) / 2√2( √2 - 1)

= 1/2√2

= √2/4

sinA.cosA = √2/4

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