Question

if tanA=2/3 then find all other trigonometric ratios​

Answer 1

Answer:

(AC)^2=(AB)^2+(BC)^2

Answer 2

Answer:

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Step-by-step explanation:

tan A =

2/3

opposite side / adjacent side =

:

By Pythagorean Theorem,

AC2 = AB2 + BC2

AC2 = 32 +22

AC2 = 9+4

AC2 = 13

AC = V13

Then,

sin A = opposite side / hypotenuse =

BC/ AC = 2//13

cos A = adjacent side / hypotenuse

AB/AC = 3/V13

csc A = 1/ sin A = V13/2

sec A 1/cos A = v13/3

cot A = 1/tan A = 3/2