Question

IF TANA=2 PROVE THAT SINA SECA + TANA - COSECA = 8-ROOT5/2

CAN ANYONE SOLVE IT ???

Answer 1

Answer:

tan=2

sinsec+tana-coseca

first draw a right angled triangle

put the sides

sin=2/root5

cos=1/root5

tan=2

sinaseca+tana-coseca

2/root5xroot5+2-root5/2

2+2-root5/2

4-root5/2

the answer will be

8-root5//2

OK friend this is urs answer.

hence proved

Answer 2

Answer:

Given that,

tanA=2/1=opposite/Adjacent

From the Pythagoras theorem,

Hy²=s²+s²

Hy²=2²+1²

Hy²=5

Hypotenuse=√5

Now,SinA=2/√5

cosA=1/√5

SecA=√5

cosecA=√5/2

From the equation,

SinA×SecA+TanA-cosecA

=2/√5×√5+2-√5/2

=2+2-√5/2

=4-√5/2

=8-√5/2

It helps you.....