Question

if tanA=3/4 and cosB=9/41 where A is in 3rd quadrant and B is in 1st quadrant then find tan(A+B)andtan(A-B)​

Answer 1

Answer:

tan(A+B)= 121.1

tan(A-B) = 119.6

Step-by-step explanation:

tanA =3/4

cosB = 9/41

where cos value isvgiven we have to find sin value as we know cos formulae is adjacent side/hypothesus so sin value is 40/41

then tan B = 160/369

tan(A+B) = 121.1

tan(A-B) = 119.6