If tanA=3/4, find the value of
1/sinA + 1/Cos A
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TanA = opp/adj = 3/4
Therefore, opp=3 , adj=4
Hypo^2 = opp^2 + adj^2
Hypo = 5
SinA = opp/hypo = 3/5
CosA = adj/hypo = 4/5
Now , 1/sinA + 1/cosA
1/ (3/5) + 1/ (4/5)
5/3 + 5/4
20+15/12
35/12————> Answer
Therefore, opp=3 , adj=4
Hypo^2 = opp^2 + adj^2
Hypo = 5
SinA = opp/hypo = 3/5
CosA = adj/hypo = 4/5
Now , 1/sinA + 1/cosA
1/ (3/5) + 1/ (4/5)
5/3 + 5/4
20+15/12
35/12————> Answer
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