Question

if tanA=3÷4,find the value of sin2A,cos2A,tan2A
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Answer 1

Answer:

the Value of Sin2A is 3/10

Cos2A is 2/5

Tan2A is 3/8

Answer 2

Answer:

sin2A = 6/5, cos2A = 8/5, tan2A = 6/4

Step-by-step explanation:

tanA=3/4

tanA=P/B

Let the length be 3k and the base be 4k

Therefore, hypotenuse=√p^2 + b^2

H = √(3k)^2 + (4k)^2

H = √9k^2 + 16k^2

H = √25k^2

H = 5k

Hence, sin2A = 2× 3k/5k

sin2A = 6/5

cos2A = 2×4k/5k

cos2A = 8/5

tan2A = 2×3k/4k

tan2A = 6/4

HOPE IT HELPS !!

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