Question

if TanA =3/4 then find 1/SinA + 1/CosA​

Answer 1

Answer:

$\tan(\alpha) = \frac{3}{4} \\ \sin(\alpha) = \frac{3}{5} \\ \cos( \alpha) = \frac{4}{5} \\ \frac{1}{ \sin( \alpha ) } + \frac{1}{ \cos( \alpha ) } = \frac{1}{ \frac{3}{5} } + \frac{1}{ \frac{4}{5} }= \frac{5}{3} + \frac{5}{4} = \frac{(20 + 15)}{12} \\ = \frac{35}{12}$

35/12 is the right answer.