Question

If tanA =3 /4,then sin2A

Answer 1

Answer:

tanA=3/4

squaring both side

tan^2A=9/16

sec^2A-1=9/16

sec^2S=25/16

cos^2A=16/25

cosA=4/5--------(1

1-sin^2A=16/25

sin^2A=9/25

sinA=3/5----------(2

since

sin2A=2sinAcosA

from 1 and 2 putting the value we get

sin2A=2*(3/5)*(4/5)

sin2A=24/25