If tanA = 3/4 , then value of sinA cosA is:
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Answered by
1
Step-by-step explanation:
tan A = perpendicular/base = 3/4
hypotenuse = ?
then,
by Pythagoras formula,
(H)2 = (P)2 + ( B)2
(H)2 = (3)2 + (4)2
(H)2 = 9 +16 = 25
H = 5
sin A = P/H = 3/5
cos A = B/H = 4/5
Answered by
6
tan A = 3/4
side opposite to A/ side adjacent to A = 3/4
BC/AB = 3/4
let the side of triangle be 3k and 4k.
∆ABC is right angled triangle.
by Pythagoras theorem,
AC² = AB² + BC²
AC = √AB² + BC²
AC = √4² + 3²
AC = √16 + 9
AC = √25
AC = 5 cm
sin A = side opposite to angle A/ hypothenuse
= BC/AC
= 3k/5k
= 3/5
cos A = side adjacent to angle A/ hypothenuse
= AB/AC
= 4k/5k
= 4/5
Hope it helps you and please mark me brainliest.
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