Question

if tanA=3 by 4 , calculate cosA and sinA​

Answer 1

Answer:

sin A = opp/hyp = 3/5 and cos A = adj/hyp = 4/5

Step-by-step explanation:

tan A = sin A/cos A

tan A = opp/adj

need to find the hypotenuse using pythogoras theorem

AC^2 = AB^2+BC^2

AC^2 = 3^2+4^2

AC^2=9+16

AC^2 = 25 AC = 5

sin A = opp/hyp = 3/5 and cos A = adj/hyp = 4/5

Answer 2

Step-by-step explanation:

tanA = 3/4 = p/b

let p = 3x & b = 4x.

h = √{(3x)^2 + (4x)^2}

h = √9x^2 + 16x^2

h = √25x^2 = 5x

cos A = b/h = 4x/5x = 4/5

sin A = p/h = 3x/5x =3/5