Question

If tanA=√3, verify that sin²A+cos²A=1

Answer 1

Given, tanA = √3

we know, tan60° = √3

so, tanA = tan60°

therefore , A = 60°

now, LHS = sin²A + cos²A

put 60° in place of A ,

= sin²60° + cos²60°

= [√3/2 ]² + [ 1/2 ]²

= 3/4 + 1/4

= (3 + 1)/4 = 4/4 = 1 = RHS

$\textbf{\underline{hence verified}}$

Answer 2

HELLO DEAR,

GIVEN:- tanA = √3

we know, tan60° = √3

so, tanA = tan60°

A = 60°

now, LHS = sin²A + cos²A

put the value of A = 60°

= sin²60° + cos²60°

= (√3/2 )² + ( 1/2 )²

= 3/4 + 1/4

= (3 + 1)/4

= 4/4

= 1 RHS

HENCE, L.H.S = R.H.S

I HOPE ITS HELP YOU DEAR,
THANKS