if tanA+4=3(4cotA+1) where 0degree
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Answer:
As sec
2
A−tan
2
A=1⇒secA=±
tan
2
A+1
=±
16
9
+1
=±
16
25
=±
4
5
⇒cosA=
secA
1
=±
5
4
And sin
2
A+cos
2
A=1
⇒sinA=±
1−cos
2
A
=±
1−
25
16
=±
25
9
=±
5
3
⇒sinAcosA=
25
12
Was
Step-by-step explanation:
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