Question

if tanA=4/3 , find sinA+cosA/cosecA​

Answer 1

Answer:

H²=P²+B²=(4k)²+(3k)²=25k²

H=5k

sinA+cosA/cosecA= 4/5 + 3/5 / 5/4= 7/5 / 5/4 =7/4

sinA+cosA/cosecA=7/4