if tanA=4/3 , find sinA+cosA/cosecA
Answers
Answered by
0
Answer:
H²=P²+B²=(4k)²+(3k)²=25k²
H=5k
sinA+cosA/cosecA= 4/5 + 3/5 / 5/4= 7/5 / 5/4 =7/4
sinA+cosA/cosecA=7/4
Similar questions