If tanA = 4/3, prove that 2 sinA - 3 cosA/ 2 sinA + 3 cosA = -1/17
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Answer:-
tan A=4/3=opposite side/adjecent side
AC²=AB²+BC²=√(4)²+(3)²=√25=5
- sin A=4/5
- cos A=3/5
now,
=>LHS
=>2 sinA - 3 cosA/ 2 sinA + 3 cosA
=>2(4/5)-3(3/5)/2(4/5)+3(3/5)
=>8/5-9/5/8/5+9/5
=>-1/5/17/5
=>-1/17
LHS=RHS
-1/17=-1/17
HENCE PROVED
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