Question

if tanA=4/3 then find the value of 4sinA-3cosA/3sinA+2cosA

Answer 1

TanA=4/3
perpendicular =4 cm
base=3cm
by pythogoras theorem
hypotenuse=5cm
sinA=4/5
cosA=3/5
in question.
$4( \frac{4}{5} ) - \frac{3( \frac{3}{5}) }{3( \frac{4}{5} )} + 2( \frac{3}{5} ) \\ \frac{16}{5} - \frac{ \frac{9}{5} }{ \frac{12}{5} } + \frac{6}{5} \\ \frac{22}{5} - \frac{9}{5} \times \frac{5}{12} \\ \frac{22}{5} - \frac{9}{12} = \frac{22}{5} - \frac{3}{4} \\ \frac{88 - 15}{20} = \frac{73}{20}$
value is 73/20

Answer 2

Answer:

Step-by-step explanation:

Answer is in the picture below