Math, asked by HarshGupt, 1 year ago

If tanA =4/3,then find the values of sin A and cos A


manshu99: tan A=3/4 its mean perpendicular is 3 and base is 4
manshu99: and hypoutnues is 5
manshu99: and sin A =perpendicular/hypatonues=3/5
manshu99: cos A= base/hypatoneus =4/5
manshu99: hope it help you to solve this prob.

Answers

Answered by krimusa7524
17
here is your answer
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manshu99: nice you are right
krimusa7524: thanks
Answered by qwvilla
2

Given: tan A =4/3

To find The values of sin A and cos A

Solution: If we consider a right-angled triangle, it has three parts perpendicular(or height), base, and hypotenuse.

In trigonometric functions,

sin A= perpendicular/hypotenuse

cos A= base/hypotenuse

tan A= perpendicular/base

∴ tan A= perpendicular/base=4/3

So perpendicular=4 and base=3

Using Pythagoras theorem, we have

(hypotenuse)²= (perpendicular)²+(base)²

⇒ (hypotenuse)²= (4)²+(3)²  [substituting the values from above]

⇒ (hypotenuse)²=16+9

⇒ (hypotenuse)²=25

⇒ hypotenuse = 5  [taking square root on both sides]

∴ sin A= perpendicular/hypotenuse = 4/5

cos A= base/hypotenuse = 3/5

Hence the values of sin A and cos A are 4/5 and 3/5 respectively.

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