If TanA = -4/3 then sinA is PLSSSS ANSWER
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Q. If TanA = -4/3 then sinA is
=> tanA = -4/3
we know that tan theta = P/B
so, by Pythagoras theorem
P² + B² = H²
(-4)² + (3)² = H²
16 + 9 = H²
H² = 25
H = 5
& sin theta = P/H
therefore,
sinA= -4/5
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