If tanA=4/5,calculate sinA and cosA
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Thanks for A2A
If cosA=4/5 then
sinA=√(1−cos2A) {Because sin^2A+cos^2A=1}
=>sinA=√(1−16/25)
=>sinA=√(9/25)
=>sinA=3/5
Now as tanA=sinA/cosA
=>tanA=3/5×5/4 {Because 1/cosA=5/4}
=>tanA=3/4
hope it's help you ✌️
gokhaleabhishek:
tq so much
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