If tanA = 4, then [tanA/(sin^3A/cosA)+sinA cosA]=?
Answers
Answered by
0
Answer:
you try and find the answer. because iam very helpless for this question.
Answered by
0
Answer:
Step-by-step explanation:
tanA/(sin^3A/cosA)+sinAcosA
=sinA/cosA/(sin^3A+sinAcos^2A)/cosA
=sinA/sinA(sin^2A+cos^2A)[Cancelling cosA and taking sinA outside]
=1/(sin^2a+cos^2A)[Cancelling sinA]
=1[Since sin^2A+cos^2A=1]
Similar questions