Question

If tanA=5/12 and angle A is an acute angle...find sinA and cosA.

Answer 1

Answer:

tan A=p/b=5/12

p=5

b=12

h=13

sinA=p/h=5/13

cosA=b/h=12/13

Answer 2

Given,

tanA = 5/12 = p/b

p = 5

b = 12

so,

h = √(p²+ b²)

h =√(25 +144)

h = √(169)

h = 13

now,

SinA = p/h = 5/13

CosA = b/h = 12/13