If tana=5÷12 and sina negative so Cosa=?
Answers
Answered by
1
tan A = 5/12 = opposite / adjacent
so, hypotenuse = square root of (opp^2 + adj.^2)
hypo. = √5^2 + 12^2
= √25+144 = √169
= 13
given that sin A is negative
sin A = opp/hypo. = - 5 / 13
cos A = adj / hypo. = - 12 / 13
so, hypotenuse = square root of (opp^2 + adj.^2)
hypo. = √5^2 + 12^2
= √25+144 = √169
= 13
given that sin A is negative
sin A = opp/hypo. = - 5 / 13
cos A = adj / hypo. = - 12 / 13
Similar questions