if tanA=5/12 find (sinA+cosA).secA
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raktimachaurasiya:
tanA=5/12 , sinA/cosA=5/12, sinA=5, cosA=12
(sinA+cosA) secA= (5+12)1/12=17/12
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Answer :
Given,
tanA = 5/12
Now,
(sinA + cosA) secA
= sinA secA + cosA secA
= sinA/cosA + 1,
since 1/cosA = secA
= tanA + 1,
since tanA = sinA/cosA
= 5/12 + 1
= (5 + 12)/12
= 17/12
#MarkAsBrainliest
Given,
tanA = 5/12
Now,
(sinA + cosA) secA
= sinA secA + cosA secA
= sinA/cosA + 1,
since 1/cosA = secA
= tanA + 1,
since tanA = sinA/cosA
= 5/12 + 1
= (5 + 12)/12
= 17/12
#MarkAsBrainliest
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