Question

If tanA = 5/12

, find the value of (sin A + cos A). secA​

Answer 1

Step-by-step explanation:

tan A = 5/12(opp/Adj)

so,

hyp=√opp2+√adj2

hyp= √(5)2+√(12)2

hyp=√25 + √144

hyp=√169

hyp= 13

Note:[ 2 indicates square; adj - adjacent; opp - opposite]

Now,

opp=5; adj=12; hyp=13....

so,

Sin A= opp/hyp = 5/13

cos A= Adj/hyp = 12/13

sec A= 1/Sin A= 13/5

now,

= [5+12/13]*13/5

=17/13*13/5

=17/5.....

hope u got the answer.....

Answer 2

Answer:

answer is 17/12

Step-by-step explanation:

tanA=5/12

perpendicular=5

base=12

hypotenuse=√25+144

=13

sinA=5/13 ,cosA=12/13 , secA= 13/12

(sinA+cosA)secA

(5/13+12/13)13/12

17*13/13*12

17/12