If tanA= 5/12 , find value of secA
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tanA=perpendicular/base
tanA=5/12
perpendicular/base=5/12
for any number k
perpendicular=5k
base=12k
(hypotenuse)²=(perpendicular)²+(base)²
hypotenuse=√{(5k)²+(12k)²}
hypotenuse=√(169k²)
hypotenuse=13k
secA=hypotenuse/base
secA=13k/12k
secA=13/12
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