Question

If TanA=5/2 than find the value of secA​

Answer 1

tan a=5/2

sec square a = tan square a+1

seca= square root of tan square a +1

seca = square root of 5/2 square +1

seca = square root of 25/4+1

sec a= square root of 29/4

seca= (square root of 29)/2

Answer 2

$\huge \bf \underline \blue {answer:}$

tanA= 5/2

CA²= AB² + BC²

( Pythagoras theorem)

CA² = 2² +5²

= 4 + 25

= 29

→CA =√29

secA = hypotenuse/adjacent side

=√29 /2