Question

if tanA=7/8 find (1+sinA)(1-sinA)/(1+cosA)(1-cosA)​

Answer 1

Answer:

64/49

Step-by-step explanation:

Using identity (a+b)(a-b) = a^2-b^2

1-sin^2A/1-cos^2A

cos^2A/sin^2A

(cosA/sinA)^2

cot^2

(1/tan)^2

(8/7)^2

64/49

Answer 2

Step-by-step explanation:

1- sin^2÷ 1-cos^2

cos^2 ÷ sin^2. {sin^2A+ cos ^2A =1 }

tan= 7/8= sin / cos

8×8÷ 7×7

64/ 49

hope it helps !!!