Question

if tanA=8/25, find sin2A, cos2A, tan2A​

Answer 1

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$\large\mathsf\red{sin2A \: = \: \frac{2tanA}{1+{tan}^{2}A}}$

$\large\mathsf\red{cos2A \: = \: \frac{1-{tan}^{2}A}{1+{tan}^{2}A}}$

$\large\mathsf\red{tan2A \: = \: \frac{2tanA}{1-{tan}^{2}A}}$

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Answer 2

Step-by-step explanation:

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