If tanA = a/b, prove that (asinA - bcosA) ÷ (asinA + bcosA) =(a²-b²) ÷ (a²+b²).
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=[(a SinA/cosA)-b(CosA/cosA)]/[(aSinA/cosA)+(bcosA/ cosA)] =[a TanA -b]/[a Tan A +b]. ...sinA/CosA=Tan A =[(a)(a/b)-b]/[a(a/b)+ b]. ....Tan A=(a/b) =[(a²/b)-b]/[(a²/b)+b]. =[(a²- b² ...
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Answer:The given statement is proved in the uploaded photo.
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