Question

If tanA = a/b, prove that (asinA - bcosA) ÷ (asinA + bcosA) =(a²-b²) ÷ (a²+b²).

Answer 1

Answer:

19-Nov-2017 · 2 answers

=[(a SinA/cosA)-b(CosA/cosA)]/[(aSinA/cosA)+(bcosA/ cosA)] =[a TanA -b]/[a Tan A +b]. ...sinA/CosA=Tan A =[(a)(a/b)-b]/[a(a/b)+ b]. ....Tan A=(a/b) =[(a²/b)-b]/[(a²/b)+b]. =[(a²- b² ...

Answer 2

Step-by-step explanation:

This is the answer

GIVEN THAT

TanA = a/b

If TanA = a/ b

$sin \: a \: = \frac{a}{ \sqrt{ {a}^{2} } + \sqrt{ {b}^{2} } }$

COS A = B / √ A^2 + b ^2

Then put the values and solve the question

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