Question

If tanA=a/b prove that costhita + sin thita/cos thita-sin thita=b+a/b-a

Answer 1

Given that,
tanA = a/b
=> sinA/cosA = a/b
therefore sinA = ax and cosA= bx where x is a common ratio
Now,
(cosA+sinA)/(cosA-sinA) = (bx+ax)/(bx-ax)
= [x(b+a)]/[x(b-a)]
= (b+a)/(b-a)
hence proved.