Question

if tanA= cot(A-18) whereA is an acute angle, find the value ofA​

Answer 1

Answer:

tan2A=cot(A−18∘)tan2A=cot(A-18∘)

⇒cot(90∘−2A)=cot(A−18∘)⇒90∘−2A=A−18∘⇒cot(90∘-2A)=cot(A-18∘)⇒90∘-2A=A-18∘

⇒108∘=3A⇒A=36∘