if tanA+cotA=2,find sinA
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Answer:
tan A+cot A=2
=> tanA+1/tanA=2
=> (tan^2A+1)/tanA=2
=> tan^2A+1=2tanA
=> tan^2A-2tanA+1=0
=> (tanA-1)^2=0
=> tanA-1=0
=> tanA=1=tan45°
=> A=45°
so, sinA=sin 45°=1/√2
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