If tanA + cotA =2
Find sinA + cosA
Answers
Answered by
0
Answer:
Step-by-step explanation:
tanA + cotA = 2
sinA / cosA + cosA / sinA = 2
sin²A + cos²x / sinA × cosA = 2
1 /sinAcosA = 2
1 = 2sinA cosA
•°• 2sinA cosA = sin2A
hence, sin2A= 1
sin2A = sin90°
2A = 90°
A = 45°
hence, sinA = sin45° = 1/√2
Answered by
1
Answer:
Step-by-step explanation:
tanA + cotA = 2
SinA/CosA + CosA/SinA = 2
Sin²A + Cos²A = 2SinACosA
2SinACosA = 1 (∵ Sin²A + Cos²A = 1)
(SinA + CosA)² = Sin²A + Cos²A + 2SinACosA
= 1 + 1
= 2
SinA + CosA = ±√2
Similar questions