Question

if tanA+ cotA = 2 find tan square A + cot square A

Answer 1

We are given tanA + cotA = 2
                  so, (tan + cotA )^2 = (2)^2
                         tan^2 A + cot^ A + 2(1) = 4       [∵tanA*cotA=1]
                   so, tan^2 A + cot^2 A = 2

Answer 2

TanA+cotA=2
tan2A+cot2A+2tanAcotA= 4
tan2A+cot2A +2=4
tan2A+cot2A=2
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