If tanA+cotA=2 find value of tan³A+7cot³
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tanA + cotA=2
tan A= 2-cotA
RHS= tan³A+7cot³
= (2-cotA)³ + cot³
= 8 - cotA³ + cotA³
= 8. { +cotA and -cotA cancelled}
hope this would helpful....mark as brainly .
tan A= 2-cotA
RHS= tan³A+7cot³
= (2-cotA)³ + cot³
= 8 - cotA³ + cotA³
= 8. { +cotA and -cotA cancelled}
hope this would helpful....mark as brainly .
kaushik6162:
this is wrong
it is crcr
(2-CotA)^3 can not be 8- cot A
s dude sry let me edit
gud answer
tq
wlcm
where did 7 go?
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