if tanA + cotA = 2, then find tan^2A + cot^2A.
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Answer:
(tanA+cotA).^2 =tan^2+cotA^2A+2tanAcotA
=tan^2A+cot^2A+2tanA×1/tanA
=tan^2A+cot^2A+2
(2).^2=tan^2A+cot^2A+2
tan^2A+cot^2A=4-2=2
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Hey there!
The following question is realted to Trigonometry.
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