Question

if tanA+cotA=2;then prove that cot^³A+tan^³A=2​

Answer 1

Answer:

here is ur answer

Step-by-step explanation:

tanA+cotA=2

=>tanA+1/tanA = 2

=>(tan^2A+1)/tanA=2

=>tan^2A+1=2tanA

=>tan^2A-2tanA+1=0

=>(tanA-1)^2=0

=>tanA-1=0

=>tanA=1

Lhs=cot^3A+tan^3A

=1/tan^3A +tan^3A

=1/1^3 + 1^3

=1+1

=2=Rhs

hence proved

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