Question

If tana+ cota= 4/ root3 , then find value of sina+ cosa

Answer 1

SinA + cosA = √3

Squaring on both sides we get,

(SinA + cosA)² = (√3)²

Sin²A + cos²A +2sinAcosA = 3

1 + 2sinAcosA = 3

2sinAcosA = 3-1

SinAcosA = 2/2

sinAcosA = 1......................(!)

tanA+cotA = 1

sinA/cosA + cosA/sinA = 1

sin²A + cos²A /sinAcosA = 1

1/sinAcosA = 1

sinAcosA = 1.....................(!!)

thus tanA + cotA = 1

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Answer 2

Answer:

1/2+root3/2

Step-by-step explanation:

tan+cota=4/root3

sina/cosa+cosa/sina=4/root3

1/sina cosa=4/root3

sin2a=sin60

a=30

sina+cosa = ?

sin30+cos30=1/2+root3/2

I hope this helps u