If tanA + cotA =5 ,find the value of tan ^2 A + cot^2A
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Step-by-step explanation:
LHS=
tanA + cotA =5
(tanA +cotA)^2=25
tan^2A +cot^2A + 2.tanA.cotA =25
tan^2A +cot^2A + 2×1=25
tan^2A +cot^2A =23
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