If tanA+cotA=5 ,then find the value of tan^2A+cot^A?
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Hey
tanA + CotA = 5
Squaring both sides ,
we get
(tanA + cotA ) ² = ( 5 ) ²
=> tan²A + Cot² A + 2 * tanA * cotA = 25
=> tan²A + Cot²A + 2 * tanA * 1 / tan²A = 25
=> tan²A + cot²A + 2 = 25
=> tan²A + cot²A = 25 - 2
=> tan²A + cot²A = 23
So ,
required answer is = 23
thanks :)
tanA + CotA = 5
Squaring both sides ,
we get
(tanA + cotA ) ² = ( 5 ) ²
=> tan²A + Cot² A + 2 * tanA * cotA = 25
=> tan²A + Cot²A + 2 * tanA * 1 / tan²A = 25
=> tan²A + cot²A + 2 = 25
=> tan²A + cot²A = 25 - 2
=> tan²A + cot²A = 23
So ,
required answer is = 23
thanks :)
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0
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