Question

If (tanA+cotA)=5 then (tan²A+cot²A)=?​

Answer 1

Answer:

refer to the image for solution hope it will help you

Answer 2

$\huge{ \bold{ \red{ \underline{Answer:-}}}}$

We know,

$\bold{(tanA+cotA)=5}$

So, applying the concept in,

(tan²A+cot²A), we get,

$= > (tan²A+cot²A) \\ = >(tanA+cotA)² - 2tanAcotA \\ = > (5) {}^{2} - 2 \times \cancel{tanA}( \frac{1}{ \cancel{tanA}} ) \\ = > 25 - 2 \\ = > \boxed{23} \bold{is \: the \: answer}$

Basic formula used:-

(a²+b²) = (a+b)² - 2ab

(or)

= (a²+b²)+2ab-2ab

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