If tanA= cotA , prove that A+B= 90°
Answers
Answered by
18
My answer will be short and to the point.
Lets see :
tanA = cotB
tan A = tan (90°- B)
A = 90°- B
A +B = 90° ⇒⇒Hence, proved
Ex :
tanA = cot A
let A + A = 90°
2A = 90°
A = 45°
∴tan 45° = 1 = cot 45°
Lets see :
tanA = cotB
tan A = tan (90°- B)
A = 90°- B
A +B = 90° ⇒⇒Hence, proved
Ex :
tanA = cot A
let A + A = 90°
2A = 90°
A = 45°
∴tan 45° = 1 = cot 45°
MayankSoni:
The question starts with tanA=cotA
it is written wrongly
nyc answer bro
thanks
Answered by
5
tanà = 1/tanà ;
tan²à = 1 ;
tanà = 1 ;
à = 45°
and similarly with variable B =45° ;
therefore , 45° + 45° = 90° h/p.
From where we can find b❔❓
It is not defined in question...
we can let it wth variable b, coz there is no variable mentioned except à.
Then how will you make a+b=90°
It can be anything
hmm good :))
we have that much liberty to solve the ques by letting it.
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