Question

if tanA=cotB,prove that A+B=90​

Answer 1

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If tanA=cotB, prove that A+B+90, where A and B are measures of acute angles.

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ANSWER

According to question,

tanA=cotB

⟹tanA=tan(90−B)

As, A, and B, are acute angles,

Then,

⟹A=90−B

⟹A+B=90

Hence proved.

Answer 2

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tanA = cotB

tanA = tan(90°–B)

A = 90° – B

.°. A + B = 90°

Hence, proved that A + B = 90°

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