Question

If tanA = cotB, prove that A+B = 90°

Answer 1

Answer:

tan A=cot B

=>tan A=tan(90- B)

=>A=90- B

=>A+B=90

Answer 2

$\huge\sf{Given\:that,}$

$\longrightarrow$$\large\sf{tan\:A=cot\:B}$

$\longrightarrow$$\large\sf{tan\:A=tan\:(90°-B)}$

$\longrightarrow$$\large\sf{A=90°-B}$

$\longrightarrow$$\huge\sf{A+B=90°}$